4u+2[4-2(u+2)]=2u-4

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Solution for 4u+2[4-2(u+2)]=2u-4 equation:


Simplifying
4u + 2[4 + -2(u + 2)] = 2u + -4

Reorder the terms:
4u + 2[4 + -2(2 + u)] = 2u + -4
4u + 2[4 + (2 * -2 + u * -2)] = 2u + -4
4u + 2[4 + (-4 + -2u)] = 2u + -4

Combine like terms: 4 + -4 = 0
4u + 2[0 + -2u] = 2u + -4
4u + 2[-2u] = 2u + -4

Remove brackets around [-2u]
4u + 2 * -2u = 2u + -4

Multiply 2 * -2
4u + -4u = 2u + -4

Combine like terms: 4u + -4u = 0
0 = 2u + -4

Reorder the terms:
0 = -4 + 2u

Solving
0 = -4 + 2u

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Add '-2u' to each side of the equation.
0 + -2u = -4 + 2u + -2u
Remove the zero:
-2u = -4 + 2u + -2u

Combine like terms: 2u + -2u = 0
-2u = -4 + 0
-2u = -4

Divide each side by '-2'.
u = 2

Simplifying
u = 2

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